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Question: Answered & Verified by Expert
An elevator in a building can carry a maximum of 10 persons, with the average mass of each person being 68 kg . The mass of the elevator itself is 920 kg and it moves with a constant speed of 3 m/s . The frictional force opposing the motion is 6000 N . If the elevator is moving up with its full capacity, the power delivered by the motor to the elevator g=10m/s2 must be at least:
PhysicsMotion In One DimensionJEE MainJEE Main 2020 (07 Jan Shift 2)
Options:
  • A 56300W
  • B 62360W
  • C 48000W
  • D 66000W
Solution:
2942 Upvotes Verified Answer
The correct answer is: 66000W
Net force on motor will be
Fm=920+6810g+6000
=22000 N
So, required power for motor
Pm=Fm.v
=22000×3
=66000 watt

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