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An endothermic reaction, $A \rightarrow B$ has an activation energy as $x \mathrm{~kJ} / \mathrm{mol}$. If the energy change of the reaction is $y \mathrm{~kJ}$, the activation energy of the reverse reaction is
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Verified Answer
The correct answer is:
$x-y$
Consider the following graph,

From the above graph
$$
\begin{aligned}
x &=y+E_{a, b} \\
E_{a, b} &=x-y \mathrm{~kJ}
\end{aligned}
$$

From the above graph
$$
\begin{aligned}
x &=y+E_{a, b} \\
E_{a, b} &=x-y \mathrm{~kJ}
\end{aligned}
$$
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