Search any question & find its solution
Question:
Answered & Verified by Expert
An engine pumps water continuously through a hose. Water leaves the hose with a velocity $y$ and $m$ is the mass per unit length of the water jet. What is the rate at which kinetic energy is imparted to water ?
Options:
Solution:
1093 Upvotes
Verified Answer
The correct answer is:
$\frac{1}{2} \mathrm{mv}^3$
Velocity of water is \(v\), mass flowing per unit length is \(m\).
Mass flowing per second \(=\mathrm{mv}\)
\(\therefore\) Rate of kinetic energy or K.E. per second
\(=1 / 2(m v) v^2=1 / 2 m v^3\)
Mass flowing per second \(=\mathrm{mv}\)
\(\therefore\) Rate of kinetic energy or K.E. per second
\(=1 / 2(m v) v^2=1 / 2 m v^3\)
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.