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An equilateral triangular loop ADC having some resistance is pulled with a constant velocity v out of a uniform magnetic field directed into the screen. At time t=0, side DC of the loop is at edge of the magnetic field. The induced current i versus time t graph will be as

PhysicsElectromagnetic InductionJEE Main
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Solution:
2812 Upvotes Verified Answer
The correct answer is:
Let 2a be the side of the triangle and b the length AE.


           


       AH AE = GH EC

∴    GH = AH AE EC

or   GH = b - vt b · a

            = a - a b vt

∴    FG = 2 GH = 2 a - a b vt

Induced emf e = Bv FG = 2 Bv a - a b vt

∴    Induced current i = e R = 2 Bv R a - a b vt

or    i = k1 - k2t

Thus, i-t graph is a straight line with negative slope and positive intercept.

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