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An equimolar mixture of toluene and chlorobenzene is treated with a mixture of conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$ and conc. $\mathrm{HNO}_{3}$. Indicate the correct statement from the following.
ChemistryHydrocarbonsWBJEEWBJEE 2012
Options:
  • A $p$ -nitrotoluene is formed in excess
  • B equimolar amounts of $p$ -nitrotoluene and p-nitrochlorobenzene are formed
  • C $p$ -nitrochlorobenzene is formed in excess
  • D $m$ -nitrochlorobenzene is formed in excess
Solution:
2360 Upvotes Verified Answer
The correct answer is: $p$ -nitrotoluene is formed in excess


As toluene and chlorobenzene, both can react with mixture of conc. $\mathrm{H}_{2} \mathrm{SO}_{4}$ and conc. HNO $_{3}$. but being more reactive, toluene will yield p-nitrotoluene in excess.

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