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An ether (A), $\mathrm{C}_5 \mathrm{H}_{12} \mathrm{O}$, when heated with excess of hot concentrated $\mathrm{HI}$ produced two alkyl halides which when treated with $\mathrm{NaOH}$ yielded compounds (B) and (C). Oxidation of (B) and (C) gave a propanone and an ethanoic acid respectively. The IUPAC name of the ether (A) is :
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Verified Answer
The correct answer is:
$2-$ethoxypropane
$2-$ethoxypropane

hence the IUPAC name of compound is

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