An excess of A g N O 3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitated would be

Question

An excess of A g N O 3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium (III) chloride. The number of moles of AgCl precipitated would be, 0.002, 0.003, 0.01, 0.001

MARKS App · Accepted Answer

A g N O 3 e x c e s s + [ C r ( H 2 O ) 4 C l 2 ] C l m o l e → A g C l n = M V = 0.01 × 100 1000 = 0.001

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