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An ice berg of density $900 \mathrm{Kg} / \mathrm{m}^3$ is floating in water of density $1000 \mathrm{Kg} / \mathrm{m}^3$. The percentage of volume of ice-cube outside the water is
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$10 \%$
Let the total volume of ice-berg is $V$ and its density is $\rho$. If this ice-berg floats in water with volume $V / n$
inside it then $V_{in} \sigma g=V \rho g \Rightarrow V_{i n}=\left(\frac{\rho}{\sigma}\right) V$
or $V_{o u t}=V-V_m=\left(\frac{\sigma-\rho}{\sigma}\right) V$
$\Rightarrow \frac{V_{\text {out }}}{V}=\left(\frac{\sigma-\rho}{\sigma}\right)=\frac{1000-900}{1000}=\frac{1}{10}$
$\therefore V_{\text {out }}=10 \%$ of $V$
inside it then $V_{in} \sigma g=V \rho g \Rightarrow V_{i n}=\left(\frac{\rho}{\sigma}\right) V$
or $V_{o u t}=V-V_m=\left(\frac{\sigma-\rho}{\sigma}\right) V$
$\Rightarrow \frac{V_{\text {out }}}{V}=\left(\frac{\sigma-\rho}{\sigma}\right)=\frac{1000-900}{1000}=\frac{1}{10}$
$\therefore V_{\text {out }}=10 \%$ of $V$
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