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An ideal gas expands in volume from $1 \times 10^{-3} \mathrm{~m}^3$ to $1 \times 10^{-2} \mathrm{~m}^3$ at $300 \mathrm{~K}$ against a constant pressure of $1 \times 10^5 \mathrm{Nm}^{-2}$. The work done is
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The correct answer is:
$-900 \mathrm{~J}$
$-900 \mathrm{~J}$
Work done $=-P(\Delta V)$
$$
=-1 \times 10^5\left[10^{-2}-10^{-3}\right]=-900 \mathrm{~J}
$$
$$
=-1 \times 10^5\left[10^{-2}-10^{-3}\right]=-900 \mathrm{~J}
$$
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