Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An ideal gas heat engine is operating between 227 °C and 127 °C. It absorbs 104 J of heat at the higher temperature. The amount of heat converted into work is
PhysicsThermodynamicsNEET
Options:
  • A 2000 J
     
     
  • B 4000 J
     
     
  • C 8000 J
     
     
  • D 5600 J
     
     
Solution:
1116 Upvotes Verified Answer
The correct answer is: 2000 J
 
 
η=1-T2T1=1-127+273227+273=15

W=ηQ1=15×104 J=2000 J

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.