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Question: Answered & Verified by Expert
An ideal gas heat engine operates in Carnot cycle between \( 227^{\circ} \mathrm{C} \) and \( 127^{\circ} \mathrm{C} \). It absorbs \( 6 \times 10^{4} \) cal of heat at high temperature. Amount of heat converted to work is:
PhysicsThermodynamicsJEE Main
Options:
  • A \( 1.2 \times 10^{4} \mathrm{cal} \)
  • B \( 4.8 \times 10^{4} \mathrm{cal} \)
  • C \( 6 \times 10^{4} \mathrm{cal} \)
  • D \( 2.4 \times 10^{4} \mathrm{cal} \)
Solution:
2370 Upvotes Verified Answer
The correct answer is: \( 1.2 \times 10^{4} \mathrm{cal} \)

The performance of heat engine is expressed by means of “efficiency” η which is defined as the ratio of useful work obtained from the engine to the heat supplied to it.

Efficiency ncycle =WQ1=T2-T1T2=100500=0.2
Amount heat converted into work
= n Q 2
=0.2×6×104 cal
=1.2×104 cal

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