An ideal gas undergoes an adiabatic process. If the pressure of the gas is reduced by 0 . 1 % then the volume is changed by (Given r = C p C v = 5 3 )

Question

An ideal gas undergoes an adiabatic process. If the pressure of the gas is reduced by 0 . 1 % then the volume is changed by (Given r = C p C v = 5 3 ), 0 . 1 %, 0 . 05 %, 0 . 06 %, - 0 . 05 %

MARKS App · Accepted Answer

The relation between pressure and volume in the case of the adiabatic process, P V γ = K , now for two different conditions, P 1 V 1 γ = P 2 V 2 γ , here P 2 = P 1 × 0 . 1 100 , put the values in the above expression, P 1 × 100 P 1 × 0 . 1 = V 2 V 1 5 3 ⇒ V 2 V 1 5 3 = 1000 ⇒ V 2 V 1 = 1000 3 5 ⇒ V 2 = 0 . 6 % V 1

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