Search any question & find its solution
Question:
Answered & Verified by Expert
An ideal gas undergoes isothermal process from some initial $i$ to final state $f$. Choose the correct alternatives.
Options:
Solution:
1762 Upvotes
Verified Answer
The correct answers are:
$d U=0$
,
$d Q=d W$
$d U=0$
,
$d Q=d W$
As the isothermal process change in temperature of the system $\Delta T=0$ or $T=$ constant. For an ideal gas change in internal energy $d U=n C_v d T$
where, $n$ is number of moles and $C_v$ is specific heat cpaacity at constant volume (from first law of thermodynamics).
So, $d U($ at $\Delta T=0)=n C_v \times 0=0$
$$
\begin{aligned}
&d Q=d U+d W \\
&d Q=0+d W \\
&d Q=d W
\end{aligned}
$$
where, $n$ is number of moles and $C_v$ is specific heat cpaacity at constant volume (from first law of thermodynamics).
So, $d U($ at $\Delta T=0)=n C_v \times 0=0$
$$
\begin{aligned}
&d Q=d U+d W \\
&d Q=0+d W \\
&d Q=d W
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.