An individual homozygous for genes cd is crossed with wild type and F 1 crossed back with the double recessive. The appearance of the offspring is as follows + + → 903 cd → 897 +d → 98 c+ → 102 The distance between the genes c and d is

Question

An individual homozygous for genes cd is crossed with wild type and F 1 crossed back with the double recessive. The appearance of the offspring is as follows + + → 903 cd → 897 +d → 98 c+ → 102 The distance between the genes c and d is, 20 map units, 9.8 map units, 10.2 map units, 10 map units

MARKS App · Accepted Answer

% o f r e c o m b i n a t i o n = D i s tan c e b e t w e e n t w o g e n e s = T o t a l n o . o f r e c o m b i n a n t p h e n o t y p e s T o t a l n o . o f p r o g e n y x 100 = 200 x 100 2000 = 10 % o r 10 c M

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