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Question: Answered & Verified by Expert
An inductance coil has a reactance of 100 Ω . When an AC signal of frequency 1000 Hz is applied to the coil, the applied voltage leads the current by 45°. The self-inductance of the coil is
PhysicsElectromagnetic InductionJEE MainJEE Main 2020 (02 Sep Shift 2)
Options:
  • A 1.1×10-2 H
  • B 1.1×10-1 H
  • C 5.5×10-5 H
  • D 6.7×10-7 H
Solution:
2418 Upvotes Verified Answer
The correct answer is: 1.1×10-2 H
tanθ=xLR=tan45°
xL=R
=100=xL2+R2
100=R2+R2
2R=100
R=502
xL=502
=502
L=5022π×1000=252πmH
=1.1×10-2H

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