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An inductive circuit contains a resistance of $10 \Omega$ and an inductance of $2.0 \mathrm{H}$. Ifan $\mathrm{AC}$ voltage of $120 \mathrm{~V}$ and frequency of $60 \mathrm{~Hz}$ is applied to this circuit, the current in the circuit would be nearly
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$0.16 \mathrm{~A}$
Here, impedence $\mathrm{z}=\sqrt{R^{2}+X_{L}^{2}}$
$\therefore \sqrt{(10)^{2}+(2 \pi \times 60 \times 2)^{2}}=753.7$
$\therefore$ Current $\mathrm{i}=\frac{V}{Z}=\frac{120}{753.7}=0.159 \mathrm{~A}$
$\therefore \sqrt{(10)^{2}+(2 \pi \times 60 \times 2)^{2}}=753.7$
$\therefore$ Current $\mathrm{i}=\frac{V}{Z}=\frac{120}{753.7}=0.159 \mathrm{~A}$
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