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An inductive circuit contains resistance of $10 \Omega$ and an inductance of $20 \mathrm{H}$. If an ac voltage of $120 \mathrm{~V}$ and frequency $60 \mathrm{~Hz}$ is applied to this circuit, the current would be nearly
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$0.016 \mathrm{amp}$
$i=\frac{V}{\sqrt{R^2+\omega^2 L^2}}=\frac{120}{\sqrt{100+4 \pi^2 \times 60^2 \times 20^2}}=0.016 \mathrm{~A}$
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