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An inductor $1 \mathrm{H}$ is connected across $220 \mathrm{~V}$, $50 \mathrm{~Hz}$ supply. Peak value of current is approximately
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$1 \mathrm{~A}$
Given, $L=1 \mathrm{H}, V=220 \mathrm{~V}, f=50 \mathrm{~Hz}$
Peak value of current $I_{0}=\frac{V_{0}}{X_{L}}=\frac{V_{0}}{\omega L}$
$\Rightarrow I_{0}=\frac{\sqrt{2} V}{2 \pi f L}=\frac{\sqrt{2} \times 220}{2 \times \pi \times 50 \times 1} \simeq 1 \mathrm{~A}$
Peak value of current $I_{0}=\frac{V_{0}}{X_{L}}=\frac{V_{0}}{\omega L}$
$\Rightarrow I_{0}=\frac{\sqrt{2} V}{2 \pi f L}=\frac{\sqrt{2} \times 220}{2 \times \pi \times 50 \times 1} \simeq 1 \mathrm{~A}$
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