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Question: Answered & Verified by Expert
An inductor and a resistor of $25 \Omega$ are connected in series to an ac source of voltage $100 \sin (100 \pi \mathrm{t})$ volt. If the impedance of the circuit is $50 \Omega$, the average power dissipated per cycle in the circuit is
PhysicsAlternating CurrentAP EAMCETAP EAMCET 2023 (17 May Shift 2)
Options:
  • A $10 \mathrm{~W}$
  • B $25 \mathrm{~W}$
  • C $50 \mathrm{~W}$
  • D $100 \mathrm{~W}$
Solution:
2171 Upvotes Verified Answer
The correct answer is: $100 \mathrm{~W}$
The average power dissipated per cycle in the circuit
$\mathrm{P}=\frac{\mathrm{V}^2}{\mathrm{Z}^2} \mathrm{R}=\frac{100^2}{50^2} \times 25=100 \mathrm{~W}$

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