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Question: Answered & Verified by Expert

An inductor of inductance L, a capacitor of capacitance C and a resistor of resistance R are connected in series to an ac source of potential difference V volt as shown in figure.Potential difference across L,C and R is 40 V,10 V and 40 V, respectively. The amplitude of current flowing through L-C-R series circuit is 102 A. The impedance of the circuit is :

PhysicsAlternating CurrentNEETNEET 2021
Options:
  • A 42Ω
  • B 5/2Ω
  • C 5Ω
  • D 4Ω
Solution:
1569 Upvotes Verified Answer
The correct answer is: 5Ω

V=VR2+VC-VL2

=402+(10-40)2

=50 volt

irms=VrmsZ

  Z=vrmsirms

  Z=Vrms×210

Z=2×50102

Z=5 Ω

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