An inverted bell, lying at the bottom of lake 47 .6 m deep, has 50 cm 3 of air trapped in it. The bell is brought to the surface of lake. The volume of the trapped air will become (atmospheric pressure = 70 cm of Hg and density of Hg = 13.6 g / cm 3 )

Question

An inverted bell, lying at the bottom of lake 47 .6 m deep, has 50 cm 3 of air trapped in it. The bell is brought to the surface of lake. The volume of the trapped air will become (atmospheric pressure = 70 cm of Hg and density of Hg = 13.6 g / cm 3 ), 350 cm 3, 300 cm 3, 250 cm 3, 22 cm 3

MARKS App · Accepted Answer

According to Boyle's law, pressure and volume are inversely proportional to each other i.e. p ∝ 1 v ⇒ P 1 V 1 = P 2 V 2 ⇒ ( P 0 + h ρ w g ) V 1 = P 0 V 2 ⇒ V 2 = ( 1 + h ρ w g P 0 ) V 1 V 2 = 1 + 47.6 * 1 * 1000 * 10 70 * 10 − 2 * 13.6 * 1000 * 10 V 1 [ A s P 2 = P 0 = 70 c m o f H g = 70 * 10 − 2 * 13.6 * 1000 * 10 ] ⇒ V 2 = 1 + 5 5 0 cm 3 = 3 0 0 cm 3

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