An inverted bell, lying at the bottom of lake 47 . 6 m deep, has 50 cm 3 of air trapped in it. The bell is brought to the surface of the lake, then the volume of the trapped air will become [atmospheric pressure = 70 cm of Hg and density of Hg = 13 . 6 g cm - 3 ]

Question

An inverted bell, lying at the bottom of lake 47 . 6 m deep, has 50 cm 3 of air trapped in it. The bell is brought to the surface of the lake, then the volume of the trapped air will become [atmospheric pressure = 70 cm of Hg and density of Hg = 13 . 6 g cm - 3 ], 600 cm 3, 300 cm 3, 250 cm 3, 200 cm 3

MARKS App · Accepted Answer

According to Boyle's law, pressure and volume are inversely proportional to each other i.e. p ∝ 1 v ⇒ P 1 V 1 = P 2 V 2 ⇒ ( P 0 + h ρ w g ) V 1 = P 0 V 2 ⇒ V 2 = ( 1 + hρ w g P 0 ) V 1 V 2 = ( 1 + 47.6 * 1 * 1000 * 10 70 * 10 − 2 * 13.6 * 1000 * 10 ) [ A s P 2 = P 0 = 70 cm of Hg = 70 * 10 − 2 * 13.6 * 1000 * 10 ] ⇒ V 2 = 1 + 5 5 0 cm 3 = 3 0 0 cm 3

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