As electric field will accelerate +ve charge along +ve x- axis and -ve charge along -ve x axis from $\overrightarrow{\text{F}}=\text{q}\left(\overrightarrow{\text{v}}\times \overrightarrow{\text{B}}\right)$ direction of $q(\overrightarrow{V}\times \overrightarrow{B})$  will be same for both of them i.e. $-\mathrm{ve} \mathrm{y}$ direction so both will deflect towards $-\mathrm{ve} \mathrm{y}$ direction.