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An iron rod is placed parallel to magnetic field of intensity $2000 \frac{\mathrm{A}}{\mathrm{m}}$. The magnetic flux through the rod is $6 \times 10^{-4} \mathrm{~Wb}$ and its cross-sectional area is $3 \mathrm{~cm}^{2}$. The magnetic permeability of the rod in $\frac{\mathrm{Wb}}{\mathrm{A}-\mathrm{m}}$ is
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$10^{-3}$
$\mu=\frac{B}{H}=\frac{\phi}{A H}=\frac{6 \times 10^{-4}}{3 \times 10^{-4}} \times \frac{1}{2 \times 10^{3}}=10^{-3}$
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