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An L.P.G. cylinder contains 15 kg of butane gas at and 10 atmospheric pressure. It was leaking and its pressure fell down to 8 atmospheric pressure after one day. The gas leaked is
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1504 Upvotes
Verified Answer
The correct answer is:
3 kg
From ideal gas equation,
(Hence V and T are constant)
and further, number of mol of gas (n) weight of the gas (w)
So
or
or x = 12 kg
Hence, the gas leaked = 15 – 12 = 3 kg.
(Hence V and T are constant)
and further, number of mol of gas (n) weight of the gas (w)
So
or
or x = 12 kg
Hence, the gas leaked = 15 – 12 = 3 kg.
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