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Question: Answered & Verified by Expert
An NPN transistor is used in common emitter configuration as an amplifier with 1 kΩ load resistance. Signal voltage of 10 mV is applied across the base-emitter. This produces a 3 mA change in the collector current and 15 μA  change in the base current of the amplifier. The input resistance and voltage gain are:
PhysicsSemiconductorsJEE MainJEE Main 2019 (09 Apr Shift 1)
Options:
  • A 0.33 kΩ, 1.5
  • B 0.67 kΩ, 300
  • C 0.67 kΩ, 200
  • D 0.33 k Ω, 300
Solution:
1332 Upvotes Verified Answer
The correct answer is: 0.67 kΩ, 300

load resistace=output resistaceRL=1kΩ=1000Ω
 input voltage=ΔVi=10mV=10×10-3V
input current=base current=ΔiB=15μA=15×10-6A
output current=collector current=ΔiC=3mA=3×10-3A
ΔiBRi=ΔVi=0.67kΩ
Ri=10×10-315×10-6=0.67kΩ
Voltage gain =ΔICRLΔVi=3×10-3×100010×10-3=300

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