An n p n transistor operates as a common emitter amplifier with a power gain of 10 6 . The input circuit resistance is 100 Ω and the output load resistance is 10 k Ω . The common emitter current gain β will be (Round off to the Nearest Integer)

Question

An n p n transistor operates as a common emitter amplifier with a power gain of 10 6 . The input circuit resistance is 100 Ω and the output load resistance is 10 k Ω . The common emitter current gain β will be (Round off to the Nearest Integer),

MARKS App · Accepted Answer

10 6 = β 2 × R 0 R i 10 6 = β 2 × 10 4 10 2 β 2 = 10 4 ⇒ β = 100

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