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An object is mounted on a wall. Its image of equal size is to be obtained on a parallel wall with the help of a convex lens placed between these walls. The lens is kept at distance $x$ in front of the second wall. The required focal length of the lens will be
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The correct answer is:
$\frac{x}{2}$
Height of image of object equal to height of object for convex lens.
If object is placed at $2 f$
$2 f=x$
$f=\frac{x}{2}$
If object is placed at $2 f$
$2 f=x$
$f=\frac{x}{2}$
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