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An object is placed $60 \mathrm{~cm}$ in front of a convex mirror of focal length $30 \mathrm{~cm}$. A plane mirror is now placed facing the object in between the object and the convex mirror such that it covers lower half of the convex mirror. What should be the distance of the plane mirror from the object so that there will be no parallax between the images formed by the two mirrors?
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Verified Answer
The correct answer is:
$40 \mathrm{~cm}$
Hint:
$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$
$\frac{1}{v}-\frac{1}{60}=\frac{1}{30}$
$\mathrm{v}=\frac{60}{3}=\pm 20 \mathrm{~cm}$
$\therefore$ Distance between object and image $=60+20=80 \mathrm{~cm}$ $\therefore x=40 \mathrm{~cm}$
$\frac{1}{v}+\frac{1}{u}=\frac{1}{f}$
$\frac{1}{v}-\frac{1}{60}=\frac{1}{30}$
$\mathrm{v}=\frac{60}{3}=\pm 20 \mathrm{~cm}$
$\therefore$ Distance between object and image $=60+20=80 \mathrm{~cm}$ $\therefore x=40 \mathrm{~cm}$
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