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An object is placed at $20 \mathrm{~cm}$ from a convex mirror of focal length $10 \mathrm{~cm}$. The image formed by the mirror is
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Virtual and at $20 / 3 \mathrm{~cm}$ from the mirror
$u=-20 \mathrm{~cm}, f=+10 \mathrm{~cm}$ also $\frac{1}{f}=\frac{1}{v}+\frac{1}{u}$
$\Rightarrow \frac{1}{+10}=\frac{1}{v}+\frac{1}{(-20)} \Rightarrow v=\frac{20}{3} \mathrm{~cm} ;$ virtual image.
$\Rightarrow \frac{1}{+10}=\frac{1}{v}+\frac{1}{(-20)} \Rightarrow v=\frac{20}{3} \mathrm{~cm} ;$ virtual image.
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