Search any question & find its solution
Question:
Answered & Verified by Expert
An observer moves towards a stationary source of sound with a speed $\frac{1}{5} t h$ that of sound. The frequency of the sound emitted by the source is $f$. The apparent frequency recorded by the observer is
Options:
Solution:
2382 Upvotes
Verified Answer
The correct answer is:
$1.2 f$
$$
\mathrm{v}_0=\frac{\mathrm{v}}{5}
$$
Apparent frequency:
$$
\begin{aligned}
& \mathrm{v}=\frac{\text { Relative frequency of observer }}{\text { Relative frequency of source }} \times(\mathrm{f}) \\
& \mathrm{v}=\left(\frac{\frac{\mathrm{v}}{5}+\mathrm{v}}{\mathrm{v}}\right) \times(\mathrm{f}) \\
& =\frac{6 \mathrm{v}}{5 \mathrm{v}} \times \mathrm{f}=1.2 \mathrm{f}
\end{aligned}
$$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.