Join the Most Relevant JEE Main 2025 Test Series & get 99+ percentile! Join Now
Search any question & find its solution
Question: Answered & Verified by Expert
An open pipe is in resonance in 2nd harmonic with frequency f1. Now one end of the tube is closed and frequency is increased to f2 such that the resonance again occurs in nth harmonic. Choose the correct option.
PhysicsWaves and SoundJEE Main
Options:
  • A n = 3 f 2 = 3 4 f 1
  • B n = 3 f 2 = 5 4 f 1
  • C n = 5 f 2 = 5 4 f 1
  • D n = 5 f 2 = 3 4 f 1
Solution:
2816 Upvotes Verified Answer
The correct answer is: n = 5 f 2 = 5 4 f 1
f 1 = v l  (2nd harmonic of open pipe)

f 2 = n v 4 l  (nth harmonic of closed pipe)

Here, n is odd and f 2 > f 1

It is possible when n = 5

because with n = 5

f 2 = 5 4 v l = 5 4 f 1

Looking for more such questions to practice?

Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.