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An optically active compound ' $\mathrm{X}$ ' has molecular formula $\mathrm{C}_{4} \mathrm{H}_{8} \mathrm{O}_{3}$. It evolves $\mathrm{CO}_{2}$ with aqueous $\mathrm{NaHCO}_{3} .{ }^{\prime} X$ ' reacts with $\mathrm{LiAlH}_{4}$ to give an achiral compound.' $X$ ' is
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Since, $\mathrm{X} \stackrel{\mathrm{NaHCO}_{3}}{\longrightarrow} \mathrm{CO}_{2}$ Hence, it must contain - $\mathrm{COOH}$ group.
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