An organ pipe open at one end and closed at other, has a length L . The wavelengths of the three lowest resonating frequencies that can be produced by this pipe are

Question

An organ pipe open at one end and closed at other, has a length L . The wavelengths of the three lowest resonating frequencies that can be produced by this pipe are, 4 L , 2 L , L, 2 L , L , L / 2, 2 L , L , 2 L / 3, 4 L , 4 L / 3 , 4 L / 5

MARKS App · Accepted Answer

L = ( 2 n − 1 ) λ 4 λ = 4 L ( 2 n − 1 ) Hence, λ 1 = 4 L 2 ( 1 ) − 1 = 4 L λ 2 = 4 L 4 − 1 = 4 L 3 λ 3 = 4 L 6 − 1 = 4 L 5

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