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An organic compound ' $A$ ' on treatment with $\mathrm{NH}_3$ gives ' $B$ ' which on heating gives ' $C$ ', ' $C$ ' when treated with $\mathrm{Br}_2$ in the presence of $\mathrm{KOH}$ produces ethylamine. Compound ' $A$ ' is
Options:
- A $\mathrm{CH}_3 \mathrm{COOH}$
- B $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{COOH}$
- C
- D $\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}$
Solution:
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Verified Answer
The correct answer is:
$\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}$
The organic compound ' $A$ ' is propanoic acid $\left(\mathrm{CH}_3 \mathrm{CH}_2 \mathrm{COOH}\right)$.
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