An organic compound contains C = 40 % , H = 13.33 % and N = 46.67 % . Its empirical formula is

Question

An organic compound contains C = 40 % , H = 13.33 % and N = 46.67 % . Its empirical formula is, C 2 H 2 N, C 3 H 7 N, C H 4 N, C H N

MARKS App · Accepted Answer

Elements Percent by mass Atomtextc mass Relative number of moles of elements Simplest molar ratio C 40 12 40 12 = 3.33 3.33 3.33 = 1 H 13.33 1 13.33 1 = 13.33 13.33 3.33 = 4 N 46.67 14 46.67 14 = 3.33 3.33 3.33 = 1 Hence, empirical ratio is C H 4 N .

Elements	Percent by mass	Atomtextc mass	Relative number of moles of elements	Simplest molar ratio
$C$	$40$	$12$	$\frac{40}{12} = 3.33$	$\frac{3.33}{3.33} =$ 1
$H$	$13.33$	$1$	$\frac{13.33}{1} = 13.33$	$\frac{13.33}{3.33} = 4$
$N$	$46.67$	$14$	$\frac{46.67}{14} = 3.33$	$\frac{3.33}{3.33} = 1$

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