An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be

Question

An organic compound contains carbon, hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be, CHO, C H 4 O, C H 3 O, C H 2 O

MARKS App · Accepted Answer

Element % Atomic mass mole ratio simple ratio C 38.71 12 38.71 12 = 3.22 3.22 3.22 = 1 H 9.67 1 9.67 1 = 9.67 9.67 3.22 = 3 O 51.62 16 51.62 16 = 3.22 3.22 3.22 = 1 Hence empirical formula of the compound would be C H 3 O .

Element	%	Atomic mass	mole ratio	simple ratio
$C$	38.71	$12$	$\frac{38.71}{12} = 3.22$	$\frac{3.22}{3.22} = 1$
$H$	9.67	$1$	$\frac{9.67}{1} = 9.67$	$\frac{9.67}{3.22} = 3$
$O$	51.62	$16$	$\frac{51.62}{16} = 3.22$	$\frac{3.22}{3.22} = 1$

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