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Question: Answered & Verified by Expert
An organic compound is subjected to chlorination to get compound A using 5.0 g of chlorine. When 0.5 g of compound A is reacted with AgNO3 [Carius Method], the percentage of chlorine in compound A is when it forms 0.3849 g of AgCl. (Round off to the Nearest Integer)
(Atomic masses of Ag and Cl are 107.87 and 35.5 respectively)
ChemistryGeneral Organic ChemistryJEE MainJEE Main 2021 (27 Jul Shift 1)
Solution:
2869 Upvotes Verified Answer
The correct answer is: 19

nCl in compound =nAgCl=0.3849 g(107.87+35.5)g/mol

mass of chlorine =nCl×35.5=0.0953gm

% wt. of chlorine =0.09530.5×100

=19.06%

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