An oscillator circuit contains an inductor 0 .05 H and a capacitor of capacity 80 μF . When the maximum voltage across the capacitor is 200 V , the maximum current (in amperes) in the circuit is

Question

An oscillator circuit contains an inductor 0 .05 H and a capacitor of capacity 80 μF . When the maximum voltage across the capacitor is 200 V , the maximum current (in amperes) in the circuit is, 4, 8, 10, 16

MARKS App · Accepted Answer

Given L = 0. 05 H , C = 80 μF V m a x = 200 V ∵ Voltage equation V t = V m sin ⁡ ω t ∴ Current (i) = c d v d t = c d d t V m sin ⁡ ω t = C V m ω cos ⁡ ω t ∵ ω = 1 L C ∴ i = V m C L cos ⁡ ω t ∴ Maximum current i m , V m C L = 200 × 80 μ 0.05 i m = 8 A

Search any question & find its solution

Looking for more such questions to practice?