An α particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:

Question

An α particle, a proton and an electron have the same kinetic energy. Which one of the following is correct in case of their de-Broglie wavelength:, λ α > λ p > λ e, λ α λ p λ e, λ α = λ p = λ e, λ α > λ p λ e

MARKS App · Accepted Answer

As we know, de-Broglie wavelength is given by, λ = h p and p = 2 m K Therefore, λ = h 2 m K As kinetic energy is the same for all particles, ∴ λ ∝ 1 m ∵ m α > m p > m e λ e > λ p > λ α

Search any question & find its solution

Looking for more such questions to practice?