Search any question & find its solution
Question:
Answered & Verified by Expert
An uncharged capacitor is connected to a battery. While charging the capacitor, how much is the energy lost, from the energy supplied by the battery?
Options:
Solution:
2797 Upvotes
Verified Answer
The correct answer is:
$25 \%$
Consider the following diagram:
$\begin{aligned} & Q=C V \\ & E_{\text {capocitor }}=\frac{Q^2}{2 C}=\frac{1}{2} C V^2 \\ & W=\text { Work done by battery }=Q V=C V^2 \\ & \therefore E_{\text {loss }}=(W)-\left(E_{\text {capocitor }}\right)=C V^2-\frac{1}{2} C V^2=\frac{1}{2} C V^2=\frac{W}{2}\end{aligned}$
This is $50 \%$ off the energy supplied by the battery
$\begin{aligned} & Q=C V \\ & E_{\text {capocitor }}=\frac{Q^2}{2 C}=\frac{1}{2} C V^2 \\ & W=\text { Work done by battery }=Q V=C V^2 \\ & \therefore E_{\text {loss }}=(W)-\left(E_{\text {capocitor }}\right)=C V^2-\frac{1}{2} C V^2=\frac{1}{2} C V^2=\frac{W}{2}\end{aligned}$
This is $50 \%$ off the energy supplied by the battery
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.