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An unpolarised beam of intensity $I_{0}$ is incident on a pair of nicols making an angle of $60^{\circ}$ with each other. The intensity of light emerging from the pair is
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Verified Answer
The correct answer is:
$I_{0} / 4$
According to,Malus' law,
$\begin{array}{l}
I=I_{0} \cos ^{2} \theta=I_{0}\left(\cos 60^{\circ}\right) \\
=I_{0} \times\left(\frac{1}{2}\right)^{2}=\frac{I_{0}}{4}
\end{array}$
$\begin{array}{l}
I=I_{0} \cos ^{2} \theta=I_{0}\left(\cos 60^{\circ}\right) \\
=I_{0} \times\left(\frac{1}{2}\right)^{2}=\frac{I_{0}}{4}
\end{array}$
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