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An unsymmetrical double convex thin lens forms the image of a point object on its axis. Will the position of the image change if the lens is reversed?
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Verified Answer
Using lens Maker's formula,
$$
\frac{1}{\mathrm{f}}=(\mu-1)\left[\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right]
$$
Due to reversibility of the lens position of the image will not change
$$
\frac{1}{\mathrm{f}}=(\mu-1)\left[\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right]
$$
Due to reversibility of the lens position of the image will not change
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