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Question: Answered & Verified by Expert
An urn contains 4 red and 5 white balls. Two balls are drawn one after the other
without replacement, then the probability that both the balls are red is
MathematicsProbabilityMHT CETMHT CET 2020 (12 Oct Shift 2)
Options:
  • A $\frac{5}{6}$
  • B $\frac{1}{6}$
  • C $\frac{2}{9}$
  • D $\frac{4}{9}$
Solution:
1516 Upvotes Verified Answer
The correct answer is: $\frac{1}{6}$
Red balls $=4$ and White balls $=5 \Rightarrow$ Total balls $=4+5=9$ Two balls are drawn one after the other without replacement
$n(S)={ }^{9} C_{1} \times{ }^{8} C_{1}=9 \times 8$
$\text { Required probability }=\frac{{ }^{4} C_{1} \times{ }^{3} C_{1}}{9 \times 8}=\frac{4 \times 3}{9 \times 8}=\frac{1}{3 \times 2}=\frac{1}{6}$

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