Search any question & find its solution
Question:
Answered & Verified by Expert
Aqueous solution of metallic nitrate $X$ reacts with $\mathrm{NH}_{4} \mathrm{OH}$ to form $\mathrm{Y}$ which dissolves in excess $\mathrm{NH}_{4} \mathrm{OH}$. The resulting complex is reduced by acetaldehyde to deposit the metal. $X$ and $Y$, respectively, are
Options:
Solution:
1983 Upvotes
Verified Answer
The correct answer is:
$\mathrm{AgNO}_{3}$ and $\mathrm{Ag}_{2} \mathrm{O}$
$\mathrm{AgNO}_{3}+\mathrm{NH}_{4} \mathrm{OH} \longrightarrow \mathrm{AgOH} \frac{\mathrm{NH}_{4} \mathrm{OH}}{(\text { excess })}\left[\mathrm{Ag}\left(\mathrm{NH}_{3}\right)_{2}\right]+$
Tollen's reagent $+\mathrm{R}-\mathrm{CHO} \longrightarrow \mathrm{R}-\mathrm{COOH}$
Tollen's reagent $+\mathrm{R}-\mathrm{CHO} \longrightarrow \mathrm{R}-\mathrm{COOH}$
Looking for more such questions to practice?
Download the MARKS App - The ultimate prep app for IIT JEE & NEET with chapter-wise PYQs, revision notes, formula sheets, custom tests & much more.