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Question: Answered & Verified by Expert
$\alpha, \beta, \gamma$ are the roots of the equation $x^3-10 x^2+7 x+8=0$. Match the following and choose the correct answer.

MathematicsQuadratic EquationAP EAMCETAP EAMCET 2004
Options:
  • A $\begin{array}{cccc}\text { A } & \text { B } & \text { C } & \text { D } \\ 5 & 3 & 1 & 2\end{array}$
  • B $\begin{array}{cccc}\text { A } & \text { B } & \text { C } & \text { D } \\ 4 & 3 & 1 & 2\end{array}$
  • C $\begin{array}{cccc}\text { A } & \text { B } & \text { C } & \text { D } \\ 5 & 3 & 2 & 1\end{array}$
  • D $\begin{array}{cccc}\text { A } & \text { B } & \text { C } & \text { D } \\ 5 & 2 & 3 & 1\end{array}$
Solution:
2980 Upvotes Verified Answer
The correct answer is: $\begin{array}{cccc}\text { A } & \text { B } & \text { C } & \text { D } \\ 5 & 3 & 2 & 1\end{array}$
Since α, β and γ are the roots of the equation


On squaring equation (i) both sides, we get


$\begin{aligned} & \text { Again now, } \frac{\alpha}{\beta \gamma}+\frac{\beta}{\gamma \alpha}+\frac{\gamma}{\alpha \beta} \\ & =\frac{\alpha^2+\beta^2+\gamma^2}{\alpha \beta \gamma}=\frac{86}{-8} \quad \text { [from Eqs (iii) and (iv)] } \\ & =-\frac{43}{4}\end{aligned}$
From the above discussion we see that option (3) is
correct.

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