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Area bounded by the curve $y=\log x$ and the coordinate axes is
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2777 Upvotes
Verified Answer
The correct answer is:
$2 \sqrt{2}$
Observing the graph of $\log x$, we find that the required area lies below $\mathrm{X}$-axis between $\mathrm{x}=0$ and $x=1$.
$$
\begin{aligned}
& \text { Sorequired area }=\left|\int_0^1 \log x d x\right|=\left.|(x \log x-x)|\right|_0 ^1 \\
& =|-1|=1
\end{aligned}
$$
$$
\begin{aligned}
& \text { Sorequired area }=\left|\int_0^1 \log x d x\right|=\left.|(x \log x-x)|\right|_0 ^1 \\
& =|-1|=1
\end{aligned}
$$
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