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Area bounded by the curve $y=\log x, x$ - axis and the ordinates $x=1, x=2$ is
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$(\log 4-1)$ sq. unit
$\begin{aligned} & \text { Given curve } y=\log x \text { and } x=1, x=2 . \\ & \text { Hence required area }=\int_1^2 \log x d x=(x \log x-x)_1^2 \\ & =2 \log 2-1=(\log 4-1) \text { sq. Unit. }\end{aligned}$
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