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Area of the ellipse $\frac{x^{2}}{25}+\frac{y^{2}}{16}=1$ is given by
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Verified Answer
The correct answer is:
$20 \pi$ sq units
We have,
$\frac{x^{2}}{25}+\frac{y^{2}}{16}=1$
Here, $\quad a^{2}=25 \Rightarrow a=5$
$b^{2}=16 \Rightarrow b=4$
So, required area $=\pi a b$
$$
\begin{aligned}
&=\pi(5)(4) \\
&=20 \pi \text { sq units }
\end{aligned}
$$
$\frac{x^{2}}{25}+\frac{y^{2}}{16}=1$
Here, $\quad a^{2}=25 \Rightarrow a=5$
$b^{2}=16 \Rightarrow b=4$
So, required area $=\pi a b$
$$
\begin{aligned}
&=\pi(5)(4) \\
&=20 \pi \text { sq units }
\end{aligned}
$$
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