Area of the triangle formed by the line $x+y=3$ and angle bisectors of the pair of straight lines $x^2-y^2+2 y=1$ is

Question

Area of the triangle formed by the line $x+y=3$ and angle bisectors of the pair of straight lines $x^2-y^2+2 y=1$ is, 2 sq. units, 4 sq. units, 6 sq. units, 8 sq. units

MARKS App · Accepted Answer

$\mathrm{x}^2-\mathrm{y}^2+2 \mathrm{y}=1 \Rightarrow \mathrm{x}= \pm(\mathrm{y}-1)$ Bisectors of above line are $x=0 ~\&~ y=1$ So area between $x=0, y=1 ~\&~ x+y=3$ is shaded Region shown in figure. Area $=1 / 2 \times 2 \times 2=2$ sq. units

Search any question & find its solution

Looking for more such questions to practice?